Source code for pyomo.util.calc_var_value

# ____________________________________________________________________________________
#
# Pyomo: Python Optimization Modeling Objects
# Copyright (c) 2008-2026 National Technology and Engineering Solutions of Sandia, LLC
# Under the terms of Contract DE-NA0003525 with National Technology and Engineering
# Solutions of Sandia, LLC, the U.S. Government retains certain rights in this
# software.  This software is distributed under the 3-clause BSD License.
# ____________________________________________________________________________________

from pyomo.common.errors import IterationLimitError
from pyomo.common.numeric_types import native_numeric_types, native_complex_types, value
from pyomo.core.expr.calculus.derivatives import differentiate
from pyomo.core.base.constraint import Constraint

import logging

logger = logging.getLogger(__name__)

_default_differentiation_mode = differentiate.Modes.sympy
_symbolic_modes = {
    None,
    differentiate.Modes.sympy,
    differentiate.Modes.reverse_symbolic,
}


[docs] def calculate_variable_from_constraint( variable, constraint, eps=1e-8, iterlim=1000, linesearch=True, alpha_min=1e-8, diff_mode=None, ): """Calculate the variable value given a specified equality constraint This function calculates the value of the specified variable necessary to make the provided equality constraint feasible (assuming any other variables values are fixed). The method first attempts to solve for the variable value assuming it appears linearly in the constraint. If that doesn't converge the constraint residual, it falls back on Newton's method using exact (symbolic) derivatives. Notes ----- This is an unconstrained solver and is NOT guaranteed to respect the variable bounds or domain. The solver may leave the variable value in an infeasible state (outside the declared bounds or domain bounds). Parameters: ----------- variable: :py:class:`VarData` The variable to solve for constraint: :py:class:`ConstraintData` or relational expression or `tuple` The equality constraint to use to solve for the variable value. May be a `ConstraintData` object or any valid argument for ``Constraint(expr=<>)`` (i.e., a relational expression or 2- or 3-tuple) eps: `float` The tolerance to use to determine equality [default=1e-8]. iterlim: `int` The maximum number of iterations if this method has to fall back on using Newton's method. Raises RuntimeError on iteration limit [default=1000] linesearch: `bool` Decides whether or not to use the linesearch (recommended). [default=True] alpha_min: `float` The minimum fractional step to use in the linesearch [default=1e-8]. diff_mode: :py:enum:`pyomo.core.expr.calculus.derivatives.Modes` The mode to use to differentiate the expression. If unspecified, defaults to `Modes.sympy` Returns: -------- None """ # Leverage all the Constraint logic to process the incoming tuple/expression if not getattr(constraint, 'ctype', None) is Constraint: constraint = Constraint(expr=constraint, name=type(constraint).__name__) constraint.construct() if constraint.is_indexed(): raise ValueError( 'calculate_variable_from_constraint(): constraint must be a ' 'scalar constraint or a single ConstraintData. Received ' f'{constraint.__class__.__name__} ("{constraint.name}")' ) body = constraint.body lower = constraint.lb upper = constraint.ub if lower != upper: raise ValueError(f"Constraint '{constraint}' must be an equality constraint") _invalid_types = set(native_complex_types) _invalid_types.add(type(None)) if variable.value is None: # Note that we use "skip_validation=True" here as well, as the # variable domain may not admit the calculated initial guesses, # and we want to bypass that check. if variable.lb is None: if variable.ub is None: # no variable values, and no lower or upper bound - set # initial value to 0.0 variable.set_value(0, skip_validation=True) else: # no variable value or lower bound - set to 0 or upper # bound whichever is lower variable.set_value(min(0, variable.ub), skip_validation=True) elif variable.ub is None: # no variable value or upper bound - set to 0 or lower # bound, whichever is higher variable.set_value(max(0, variable.lb), skip_validation=True) else: # we have upper and lower bounds if variable.lb <= 0 and variable.ub >= 0: # set the initial value to 0 if bounds bracket 0 variable.set_value(0, skip_validation=True) else: # set the initial value to the midpoint of the bounds variable.set_value( (variable.lb + variable.ub) / 2.0, skip_validation=True ) # store the initial value to use later if necessary orig_initial_value = variable.value # solve the common case where variable is linear with coefficient of 1.0 x1 = value(variable) # Note: both the direct (linear) calculation and Newton's method # below rely on a numerically valid initial starting point. # While we have strategies for dealing with hitting numerically # invalid (e.g., sqrt(-1)) conditions below, if the initial point is # not valid, we will allow that exception to propagate up try: residual_1 = value(body) except: logger.error( "Encountered an error evaluating the expression at the " "initial guess.\n\tPlease provide a different initial guess." ) raise try: variable.set_value(x1 - (residual_1 - upper), skip_validation=True) residual_2 = value(body, exception=False) except OverflowError: # If we encounter an error while evaluating the expression at the # linear intercept calculated assuming the derivative was 1. This # is most commonly due to nonlinear expressions (like sqrt()) # becoming invalid/complex. We will skip the rest of the # "shortcuts" that assume the expression is linear and move directly # to using Newton's method. residual_2 = None if residual_2.__class__ not in _invalid_types: # if the variable appears linearly with a coefficient of 1, then we # are done if abs(residual_2 - upper) < eps: # Re-set the variable value to trigger any warnings WRT the # final variable state variable.set_value(variable.value) return # Assume the variable appears linearly and calculate the coefficient x2 = value(variable) slope = float(residual_1 - residual_2) / (x1 - x2) intercept = (residual_1 - upper) - slope * x1 if slope: variable.set_value(-intercept / slope, skip_validation=True) try: body_val = value(body, exception=False) except OverflowError: body_val = None if body_val.__class__ not in _invalid_types and abs(body_val - upper) < eps: # Re-set the variable value to trigger any warnings WRT # the final variable state variable.set_value(variable.value) return # Variable appears nonlinearly; solve using Newton's method # # restore initial value variable.set_value(orig_initial_value, skip_validation=True) expr = body - upper expr_deriv = None if diff_mode in _symbolic_modes: try: expr_deriv = differentiate( expr, wrt=variable, mode=diff_mode or _default_differentiation_mode ) except: if diff_mode is None: # If the user didn't care how we differentiate, try to # (mostly silently) revert to numeric differentiation. logger.debug( 'Calculating symbolic derivative of expression failed. ' 'Reverting to numeric differentiation' ) diff_mode = differentiate.Modes.reverse_numeric else: raise if type(expr_deriv) in native_numeric_types and expr_deriv == 0: raise ValueError( f"Variable '{variable}' derivative == 0 in constraint " f"'{constraint}', cannot solve for variable" ) if expr_deriv is None: fp0 = differentiate(expr, wrt=variable, mode=diff_mode) else: fp0 = value(expr_deriv) if abs(value(fp0)) < 1e-12: raise ValueError( f"Initial value for variable '{variable}' results in a derivative " f"value for constraint '{constraint}' that is very close to zero.\n" "\tPlease provide a different initial guess." ) iter_left = iterlim fk = residual_1 - upper while abs(fk) > eps and iter_left: iter_left -= 1 if not iter_left: raise IterationLimitError( f"Iteration limit (%s) reached solving for variable '{variable}' " f"using constraint '{constraint}'; remaining residual = %s" % (iterlim, value(expr)) ) # compute step xk = value(variable) try: fk = value(expr) if fk.__class__ in _invalid_types and fk is not None: raise ValueError("Complex numbers are not allowed in Newton's method.") except: # We hit numerical problems with the last step (possible if # the line search is turned off) logger.error( "Newton's method encountered an error evaluating the " f"expression for constraint '{constraint}'.\n\tPlease provide a " "different initial guess or enable the linesearch if you have not." ) raise if expr_deriv is None: fpk = differentiate(expr, wrt=variable, mode=diff_mode) else: fpk = value(expr_deriv) if abs(fpk) < 1e-12: # TODO: should this raise a ValueError or a new # DerivativeError (subclassing ArithmeticError)? raise RuntimeError( "Newton's method encountered a derivative of constraint " f"'{constraint}' with respect to variable '{variable}' that was too " "close to zero.\n\tPlease provide a different initial guess " "or enable the linesearch if you have not." ) pk = -fk / fpk alpha = 1.0 xkp1 = xk + alpha * pk variable.set_value(xkp1, skip_validation=True) # perform line search if linesearch: c1 = 0.999 # ensure sufficient progress while alpha > alpha_min: # check if the value at xkp1 has sufficient reduction in # the residual try: fkp1 = value(expr, exception=False) # HACK for Python3 support, pending resolution of #879 # Issue #879 also pertains to other checks for "complex" # in this method. if fkp1.__class__ in _invalid_types: # We cannot perform computations on complex numbers fkp1 = None if fkp1 is not None and fkp1**2 < c1 * fk**2: # found an alpha value with sufficient reduction # continue to the next step fk = fkp1 break except OverflowError: # Encountered an overflow, either from evaluating # this point in the line search (to get fkp1) or # from squaring fkp1. (The example from #3540 # actually triggers both). Reject this alpha value. pass alpha /= 2.0 xkp1 = xk + alpha * pk variable.set_value(xkp1, skip_validation=True) if alpha <= alpha_min: residual = value(expr, exception=False) if residual.__class__ in _invalid_types: residual = "{function evaluation error}" raise IterationLimitError( f"Linesearch iteration limit reached solving for " f"variable '{variable}' using constraint '{constraint}'; " f"remaining residual = {residual}." ) # # Re-set the variable value to trigger any warnings WRT the final # variable state variable.set_value(variable.value)